a bust starts from rest. if the acceleration of the bus is 0.5 m/s^2, what will be it's velocity at the end of 2 minutes and what distance will it cover during that time
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t = 2 seconds
Given:-
- initial velocity u = 0 ( because the object starts from rest)
- Acceleration = 0.5m^2
- Time = 2 seconds
To Find :-
- The Final Velocity and the distance travelled .
Solution:-
We know that acceleration = Change in velocity.
→From the First equation of the motion= v =u+at
→v = 0+0.5*2 = 1 m/s
→Hence v = 1 m/s
Now,
The second equation of motion s = ut+1/2at2
→s = 1/2*2+1/2*0.5*2*2
→ Distance s = 1meter
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