Question

| a+bw+cw^2/a+bw^2+cw |​

Answer 1

Answer:

Step-by-step explanation:

(a+bω+cω2)(a+bω2+cω)=(a2+b2+c2−ab−bc−ac)

∴L.H.S.=(a+b+c)(a+bω+cω2)(a+bω2+cω)

=(a+b+c)(a2+b2+c2−ab−bc−ac)

=a3+ab2+ac2+ba2+b3+bc2+ca2+cb2+c3−a2b−abc−a2c−ab2−b2c−abc−abc−bc2−ac2

=a3+b3+c3−3abc=R.H.S.

Answer 2

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