a+c+b=180. if b=a+c find √ac
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Let sides b, c and angle A be given (b > c).
Then A +B +C = 180° => B +C = 180° -A
After this, we use Napier Analogy: tan (B -C)/2 = [(b -c)/(b+c)]cot A/2
From this (B -C)/2 and thus, B -C can be found.
Now, since B +C and B -C are known, we can find B and C by adding and subtracting. The side a can be found by using sine rule.
hope it helps u
Then A +B +C = 180° => B +C = 180° -A
After this, we use Napier Analogy: tan (B -C)/2 = [(b -c)/(b+c)]cot A/2
From this (B -C)/2 and thus, B -C can be found.
Now, since B +C and B -C are known, we can find B and C by adding and subtracting. The side a can be found by using sine rule.
hope it helps u
ClaryHerondale:
then b = 90 and a+c = 90
and a = 90-c and c = 90-a
root (90-c)(90-a)
a+c=180\2
after that I'm not able to figure out the answer
a+c=90
root (ac) = root (90-c)(90-a)
THE QUESTION IS WRONG
I'm sure
nope... what you've asked up there could be a question which makes sense.
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