Question

a) Calculate the energy transferred when 2 A current flows through a 10ohm resistor for 30 minutes.
b) Calculate the amount of charge that would flow in one hour through the element of an electric iron drawing a current of 0.4 amps.​

Answer 1

Answer:

a )

Hope this is helpful

Answer 2

(a) Given :-

Current (I) = 2A

Resistance (R) = 2ohm

Time (t) = 30mins = 1800 sec

Energy = ?

H = I^2 RT

H = 2^2 x 10 x 1800

H = 4 x 18000

H = 72000 J

•°• 7200 Joules of energy is transferred.

(b) Given :-

Time (t) = 1 hr = 3600 sec

Current (I) = 0.4 A

Charge (Q) = ?

We know that,

I = Q/T

Or,

Q = IT

Substituting values,

Q = 3600 x 0.4

Q = 1440 C

•°• A charge of 1440 C flows through the element of the electric iron.