Question

A. Calculate the heat loss or heat gain of the 3 solution mixtures (qrxn). Then calculate the ΔH for each reaction. Show your calculations.
HCl & NaOH → NaCl + H2O = 461 J
NH4Cl + NaOH → NH3 + NaCl + H2O=21.3 J
NH3 + HCl → NH4Cl=136.6 J

Answer 1

Answer:

Explanation:

Solution Mixture 1: NaOH + HCl = H2O + NaCl

i.

· Solution Mixture 2: NaOH + NH4Cl = NH3 + NACl + H2O

i.

· Solution Mixture 3: NH3 + HCl = NH4Cl

i.

AND

A. Use Hess’s Law to determine ΔH for the first 2 reactions and then add them together to determine ΔH for the third reaction: NH3 + HCl à NH4Cl.

· NaOH + HCl = H2O + NaCl

i. ΔH(rxn) = [(1 mol)(-407.27 kJ/mol) + (1 mol)(-285.83 kJ/mol)] - [(1 mol)(-425.93 kJ/mol) + (1 mol)(-92.30)]

ii. -359.47 kj/mol

· NAOH + NH4CL = NH3 + H2O

Hope it helps you...