Question

A calorimeter of water
equivalent '5g' has water of
mass 55g up to a certain
level. Another identical
calorimeter has a liquid of
mass '38g' up to same level.
As both of them cool in the
same surroundings from
50°C to 46°C, water takes 80
s to cool. If the specific heat
of water is 1 cal/g °C, the
specific heat of the liquid in
cal/g °C is​

Answer 1

Answer:

Let heat loss rate of calorimeter be a cal/s

Heat lost in 1st case =80a=60×1×(50−46)=240

=> a=3 cal/s

Let specific heat of liquid be Ccal/g−C

Heat lost in second case =32a=5×1×4+38×4C

=>C=

38×4

96−20

=0.5

Specific heat of the liquid =0.5cal/g−

∘

C

Explanation:

please mark me as brainlist and follow me

Answer 2

your answer is 0.5 cal/g centigrade

Explanation:

i hope so it is correct and helpful for you