Question

A can acceleration from rest and
reaches
a velocity of 20 m/s in 15s
1) calculate the distance travelled and this 15s​

Answer 1

Answer:

distance = 45 meters

Explanation:

given that -

initial velocity (u) - 0m/s

final velocity (v) - 20m/s

time taken (t) - 15s

distance (s) - ?

first we calculate acceleration =

v= u+at

a = v- u / t

a = 20 - 0 /15

a = 20 /15 = 4/3

distance by second equation of motion=

s = ut + 1/2at²

s = 1/2 × 4×15×15 /6

s = 45 m