Question

A can build 3 software packages in 48 days and B can build 4 software packages in 48 days. If, with the help of C, they can build 5 software packages in 20 days, then C alone can build 5 software packages in?

Answer 1

the number of days in which C alone can make 5 software packages: 48days

1.let the work done by A in a day be x

let the work done by B in a day be y

let the work done by C in a day be z

2.x=3/48

  y=4/48

  z=?

3.the work done by A in 20 days is 20x

  the work done by B in 20 days is 20y

  the work done by Z in 20 days is 20z

4.  20x+20y+20z=5

    20*(3/48)+20*(4/48)+20z=5

     from above z=5/48

5. the number of days C will take to make 5 software alone is

    5*(48/5)=48.