Question

A can complete a piece of work in 8 hours.B can complete in 10 hours and c in 12 hours.If a,b,c startsthe work together but a leaves after 2 hours.Find the time taken by b and c to complete the remaining work

Answer 1

Step-by-step explanation:

A=8 efficiency=120/8=15

B=10 lcm(8,10,12)=120 efficiency=12

C=12 efficiency=120/12=10

(A+B+C)2 days work=(15+12+10)×2

=37×2=74

Now A left the work

Remaining work=120-74=46

Time for(B+C) to do work=46/25

Answer 2

Answer:

a b c do the work in 1 HR=

1/8+1/10+1/12

=37/120

in 2 hrs a b c do 37/60 parts of the work

remaining work=

1-37/60

=23/60

b c do the work in 1 HR=

1/10+1/12

=11/60

time required by b c=

1÷11/60×23/60

=23/11hrs