A can complete a piece of work in 8 hours, b can complete in 10 hours andc in 12 hours. If a,b, c start the work together but a laves after 2 hours. Find thetime taken by b and c to complete the remaining work.
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Step-by-step explanation:
A,B,C 1 hour work is=1/8+1/10+12= 37/120
A,B,C work together for 2 hours, so,A,B,C 2 hours work is: (37/120)*2=37/60
remaining work=1-37/60=23/60 (23/60 work is done by B and C together)
B,C 1 hour work is= 1/10+1/12=11/60
23/60 hours work done by B,C= (11/60)* (60/23)=11/23
so... ans is: 2(1/11)
Hope it helps you....
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