a can complete a piece of work in 8 hours b can complete in 10 hours and c in 12 hours. if a b c start the work together but a leaves after 2 hours. find the time taken by b and c to complete the remaining work.
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Total unit work = 1/8 + 1/10 + 1/12 = (15 + 12 + 10)/120 = 37/120
Work done by all three in 2 hours = 2*37 / 120 = 74/120
Remaining work = 1 - (74/120) = 120 - 74 / 120 = 46/120 = 23/60
Now work done by B and C in 1 day = 1/10 + 1/12 = (6 + 5) / 60 = 11/60
So B and C will take = 60/11 * 23/60 = 23/11 days
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