A can complete a work in 10 days b in 12 days and c in 15 days all of them began the work together but a had to leave the work after 2 days
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55
Answer:
Step-by-step explanation:
A's work done =1/10
B's work done =1/12
C's work done =1/15 in 1 days
A+B+C=1/10+1/12+1/15= 1/4
A,B,C work for 2 days so 2*1/4=1/2
C leaves before 3 days remaining work so 3*1/15=1/5
So total work done in 5 days(3+2)=1/2+1/5=7/10
remaining work = 1-7/10=3/10
3/10 work done by B and C in x days
3/10=x(1/12+1/15)
x=2 days
So A,B,C work for 2 days
B,C WORKS for 2 days
C works for 3 days
total 2+3+2=7 Ans
Hope it helps you....
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