Question

A can complete a work in 10 days b in 12 days and c in 15 days all of them began the work together but a had to leave the work after 2 days

Answer 1

Answer:

Step-by-step explanation:

A's work done =1/10

B's work done =1/12

C's work done =1/15 in 1 days

A+B+C=1/10+1/12+1/15= 1/4

A,B,C work for 2 days so 2*1/4=1/2

C leaves before 3 days remaining work so 3*1/15=1/5

So total work done in 5 days(3+2)=1/2+1/5=7/10

remaining work = 1-7/10=3/10

3/10 work done by B and C in x days

3/10=x(1/12+1/15)

x=2 days

So A,B,C work for 2 days

B,C WORKS for 2 days

C works for 3 days

total 2+3+2=7 Ans

Hope it helps you....