Question

A bullet of mass 50 gram moving with speed of 500 metre per second is brought to rest in 0.01 seconds the average force acting on the ball is what

Answer 1

Answer:

force is 25 N

Explanation:

m = 0.05 kg

v = 500 m/s

t = 0.01 s

F = ?

by 2nd law of motion

F = ma = m v/t

F = 0.05x5 /  0.01

F = 25 N