A bullet of mass 50 gram moving with speed of 500 metre per second is brought to rest in 0.01 seconds the average force acting on the ball is what
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Answer:
force is 25 N
Explanation:
m = 0.05 kg
v = 500 m/s
t = 0.01 s
F = ?
by 2nd law of motion
F = ma = m v/t
F = 0.05x5 / 0.01
F = 25 N
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