Question

A can complete a work in 20 days and B in 30 days. A worked alone for 4 days and the B
completed the remaining work along with C in 18 days. In how many days can C complete
the work?

Answer 1

A completes 120 of the job per day.  

B completes 130 of the job per day.  

C completes 1c of the job per day.  

In 4 days, A completes 4 days ×120 jobday=15 job; 45 job remaining.  

In 18 days, B completes 18 days ×130 jobday=35 job; 15 job remaining.  

In 18 days, C completes 18 days ×1c jobday=18c job =15 job.  

c=90C can do the job alone in 90 days

Answer 2

Step-by-step explanation:

A+B's 20 day's work=

30

1

×20=

3

2

Remaining work=1−

3

2

=

3

3−2

=

3

1

Now,

3

1

rd

work is done by A in 20 days.

∴ The whole work will be done by A in 20×3=60 days.