Question

A can complete the work in 24 days b in 30 days c in 18 days . After working together for 5 days B falls sick .How long will A and C can complete the work

Answer 1

Answer:3.5 days

Given:

A can complete work in 24 days,b in 30 and c in 18 days

To find:

Time taken by A and C to complete the work

Solution:-

Total fraction of work done by a,b and c in one day

$\frac{1}{24} + \frac{1}{30} + \frac{1}{18}$

$= \frac{47}{360}$

Work completed by them is 5 days

$\frac{47}{360} \times 5$

$= \frac{47}{72}$

•After working together for 5 days B falls sick

Then, remaining work=

$1 - \frac{47}{52}$

$= \frac{72 - 47}{72}$

$= \frac{25}{72}$

Without B work done by A and C

$\frac{1}{24} + \frac{1}{18}$

$= \frac{7}{72}$

Now

Number of days for A and C to complete work

$\frac{7}{72} \div \frac{25}{72}$

$\frac{7}{72} \times \frac{72}{25}$

$\frac{7}{25}$

$3.5$

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Time taken by A and C to complete the work=3.5 days

Answer 2

Answer :-

Time taken by A and C to complete the story work = 3.5 days.

Explanation :-

A can complete the work in 24 days, B in 30 and C in 18 days.

_______________________[Given]

______________________________

To find :-

Time taken by A and C to the remaining work.

______________________________

Solution :-

Total fraction of work completed by A, B and C in one day

= 1/24 + 1/30 + 18

= 47/360

• fraction of work completed by A, B and C in 5 days

= (47/360) × 5

= 47/72

• After working together for 5 days, B falls sick

Then, remaining work

= 1 - (47/72)

= 25/72

• Without B, the completed by A and C in one day

= 1/24 + 1/18

= 25/72

No. of days for A and C to complete the remaining work

= 7/72 ÷ 25/72

= 7/72 × 72/25

= 25/7

≈ 3.5 days

_____________________________

Time taken by A and C to complete the remaining work = 3.5 days .

_____________________[Answer]