A can do 1/3 of a work in 30 days. B can do 2/5 of the same work in 24 days. They worked together for 20 days. C completed the remaining work in 8 days. Working together A, B and C will complete the same work in:
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A can do a work in 6 days and B can do it in 8 days, they worked together for 2 days and then B left the work. How many days will A require to finish the work?
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Given,
A can do a work in = 6 days
A’s, 1 day work =
6
1
B can do a work in = 8 days
B’s, 1 day work =
8
1
Both (A+B)’s 1 day work =
6
1
+
8
1
=
24
4+3
=
24
7
Both (A+B)’s 2 day work =2×
24
7
=
12
7
So, the remaining work =1−
12
7
=
12
12−7
=
12
5
Now,
It is given that,
A can do a work in 6 days
A can do
12
5
work in =6×
12
5
days
=
2
5
days
=2
2
1
days
∴A can finish the work in 2
2
1
days.
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