Question

A can do 2/3 of a certainwork in 16 days and b can do 1/4 of the same work in 3 days. In how many days can both finish the work, working together?

Answer 1

a in 24 days a total of work
b in 12 days a total of work and both can complete in 8 days

Answer 2

let the total work be 'x' units

A's 16 day's work = 2x/ 3 units

A's 1 day's work = 2x / 16 × 3 = 2x / 48

= x / 24

B's 3 days' work = 1×x/ 4

B's 1 day's work = x / 3 × 4 = x / 12

when they worked together,

(A + B)^s 1 day's work = (x / 24) + (x / 12)

= (x + 2x )/ 24 = 3x / 24 = x / 8

Answer: A and B together can finish the work in 8 days.