Question

A can do a piece of work in 80 days . He work at it for 10 days and then b alone finishes the remaining work in 42 days . In how many days could both do it with proper steps

Answer 1

Answer:

Now, A can do a piece of work in 80 days. So, let the TOTAL WORK = 80 units.

A -> 80 days = 1 unit/day

So, in 10 days, A has completed 10 units.

Remaining Work = 70 units.

Now, B finishes this in 42 days. So rate of work if B =7042 =53unit/day

Thus, A + B =1+53 = 83

So, TIME TAKEN = 8083 = 30 Days (Answer)