Question

A can do 25% of a piece of work in 12 days. if the efficiency of b is 33.33% more than the efficiency of a and if c works at half of its own efficiency then he can do the piece of work in 48 days. the piece of work is to be completed in 50 days. if a, b, and c started the work together with their full efficiency then how many days before the scheduled time will they complete the same piece of work?

Answer 1

A’s one day’s work is 1/6.

Being 25% more efficient, B can finish 1.25/6 work in one day.

So the number of days taken by B is 6/1.25 = 4.8 days.