A can do a certain work in 15 days and B
can do same work in 18 days. They work together but A had left the work after some days and B finished the remaining work in 7 days . After how many days A had left the work ?
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Answer:
6 days
Step-by-step explanation:
LCM OF (18,15)=TOTAL WORK
=90 UNIT
EFFICIENCY OF A=90/18
=5 UNIT/DAY
EFFICIENCY OF B=90/15
=6 UNIT/DAY
B WORKED FOR 10 DAYS
SO,10 DAYS WORK OF B=10X6
=60 UNITS
REMAINING WORK=90-60=30 UNITS
NOW 30 UNITS OF WORK WILL BE DONE BY A IN 30/5 DAYS
= 6 DAYS
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