Math, asked by simana072, 11 months ago

A can do a certain work in 15 days and B
can do same work in 18 days. They work together but A had left the work after some days and B finished the remaining work in 7 days . After how many days A had left the work ?

Answers

Answered by rkarulsaravanan59200
0

Answer:

6 days

Step-by-step explanation:

LCM OF (18,15)=TOTAL WORK

                        =90 UNIT

EFFICIENCY OF A=90/18

                              =5 UNIT/DAY

EFFICIENCY OF B=90/15

                              =6 UNIT/DAY

B WORKED FOR 10 DAYS

SO,10 DAYS WORK OF B=10X6

                                         =60 UNITS

REMAINING WORK=90-60=30 UNITS

NOW 30 UNITS OF WORK WILL BE DONE BY A IN 30/5 DAYS

                                         = 6 DAYS

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