a can do a piece of wok in 25 days and b can finish it in 20 days.they work togather for 5 days and then a leaves in how many days will b finish the remaining work
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Let us assume the complete work be as x
a can complete the work in 25 days
So in one day, a can do x/25 part of the work
b can complete the work in 20 days,
So in one day, a can do x/20 part of the work
In five days, work completed by both = 5*(x/25) + 5*(x/20) = x/5+x/4 = 9x/20
So 9x/20 part of the work is completed in five days.
Now, remaining work=x–9x/20 = 11x/20
Since b takes 20 days to complete ‘x’ amount of work, 11x/20 part of the work can be completed by b will be:
(11x/20)/(x/20)= 11
So, ‘b’ can complete the remaining work in 11 days
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