A can do a piece of work in 10 days and B can do in 15 days if A left the work in 5 days In how many days did B do remaining work
Answers
Step-by-step explanation:
A can work a piece of work = 10 days
1 day's work= 1/10
B can do a piece of work = 15 days
1 day's work = 1/15
total work = 5/30 = 30/5
remaining work = 1-30/5 = 25/5 = 5
ANS.... remaining work done by B = 5 days
IF HELPFUL PLS FOLLOW
Answer:
A CAN DO THE WORK IN 15 DAYS.
B CAN DO THE WORK IN 10 DAYS.
TOGETHER THEY CAN DO THE WORK IN = 1/(1/15+1/10 )=30/ ( 2+3)=6
IT IS NOT CKEAR WHETHER THEY ARE WORKING TOGETHER OR B ALONE THE WORK.
ASSUMING THAT B WORKS IN ALONE AND LEAVES AFTER 5 DAYS ,50% OF THE WORK WOULD HAVE BEEN COMPLETE.
THEN FOR COMPLETING THE BALANCE , WORK A WILL NEED =15/100 * 50 = 7 . 5DAYS.
IF THEY HAVE WORKED TOGETHER AND B LEAVES AFTER 5 DAYS , THEN 5/6 TH OF THE WORK , WOULD HAVE BEEN OVER
HENCE,
FOE FINISHING THE BALANCE WORK ,A WILL TAKE =15 * 1/6 = 2.5 DAYS.