Math, asked by SA99, 5 months ago

A can do a piece of work in 10 days and B in 20 days. They start to do the work together but after 5 days A leaves off.Remaining work is completed by B alone. How long will B take to finish the remaining work?​

Answers

Answered by Anonymous
1

Step-by-step explanation:

A. B

10 d 20

60 W

A one day work = 6

B one day work = 3

{A+ B }= 9×5 = 45 W

rem. work = 60-45

= 15 W

B = 15/3 = 5 answer

Answered by sanjusingh8056
1

Step-by-step explanation:

total days required for A =10days

" " " " B =20days

therefore,

A 1 day work = 1 and B 1 day work = 1

___ ___

10 20

(A +B) 1 day work =1/10+1/20 = 2+1

______ =3/20

20

(A +B) 5 days work =3/20×5=3/4

Remaining work = 3 4-9/4=ans

1 -- ___ =

4

Similar questions