Math, asked by Amishh7732, 1 year ago

a can do a piece of work in 10 days, b in 15 days. they work together for 5 days, the rest of the work is finished by c in two more days. if they get rs. 3000 as wages for the whole work, what are the daily wages of a, b and c respectively (in rs)? select one: a. none of these b. 300, 200, 250 c. 200, 250, 300 d. 200, 300, 400

Answers

Answered by anr4u97
14
  1. A=1/10;b=1/15
  2. they worked for 5 daysthe rest of the work is finished by c in two more days i.e,5(1/10+1/15)+2(1/c)=1
  3. from this we get c=12
  4. hence c can do a work in 12 and in 1 day c can do 1/12th work
  5. hence c=1/12
  6. if we consider ratio's of A:B:C we get 1/0:1/15:1/12
  7. hence from this we get A:B:C=6:4:5
  8. total wages paid is 3000 i.e, 6x+4x+5x=3000
  9. 15x=3000 i.e, x=200
  10. hence A gets 6x i.e, 6*200=1200
  11. B gets 4x i.e, 4*200=800
  12. C gets 5x i.e, 5*200=1000
Answered by beparidibakar777
7

Answer:

300 200 250

Step-by-step explanation:

A 10 day

B 15 day   now assume they together all work for 5 days A+B+C=5 day

A+B+C=5 day

now LCM of 10,15,5=30

so A efficiency is 3  B efficiency is 2 and A+B+C efficiency 6  how(30/10=3   30/15=2    30/5=6) now c efficiency is 1

now ratio of their wages is 3:2:1

3+2+1=6          6--------3000   so 1 value is 500

so

A's total share = Rs. 1500  

B's total share = Rs. 1000  

C's total share = Rs. 500  

A's one day's earning = Rs.300  (1500/5 day work)

B's one day's earning = Rs.200 (1000/5 day work)  

C's one day's earning = Rs.250 (500/2 day work)

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