Question

A can do a piece of work in 10days and b in 20days.They begin together but a leaves 2 days before the completion of the work. The whole work will be done in how many days?

Answer 1

The whole work will be done in 8 days.

Step-by-step explanation:

Let the work will be done in x days.

1 day work of A = 1/ 10

1 day work of B = 1/20

x - 2 / 10 + x / 20 = 1

2x - 4 + x / 20 = 1

3x - 4 = 20

3x = 24

x = 8 days

Hence the whole work will be done in 8 days.

Also learn more

A can do a piece of work in 20 days and b in 15 days. with help of c, they finish the work in 5  days. in how many days c alone can do the same work?

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Answer 2

Answer:

8 days

Step-by-step explanation:

Let the required days be x.

A works for (x - 2) days, while B works for x days.

According to the question,

$\frac{x - 2}{10} + \: \frac{x}{20} = 1$

$2x- 4 + x = 20$

$3x = 24$

$x = 8 \: days$