A Can do a piece of work in 12 days and B can do the same work in 20 days and they worked together for 3 days and then goes away . how many days will Be finish the work.
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Answered by
2
Answer:
Step-by-step explanation:There are multiple ways of doing this :
Method 1
A & B together can complete work in (25x20)/(25+20) =500/45 = 100/9 days.
They complete 5 x 9/100= 9/20 work in 5 days.
Remaining 11/20 work done by B in 11/20 x 20 = 11 days.
Method 2
A works only for 5 days completing 5/25 = 1/5 part of work.
Remaining 4/5 work is done by B in 4/5 x 20 = 16 days.
=> B works for 11 days after A leaves.
Method 3
Let B take m days after A leaves.
Since A & B work together for 5 days, we have :
5/25 + (5 + m)/20 = 1
Taking LCM as 100,
20+ 5(5 + m) = 100
=> 20 + 25 + 5m = 100
5m = 100 - 45 = 55
m = 55/5= 11 days.
Answered by
1
Answer:
a piece of work =12
can do same work = 20 days
80 ans
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