Math, asked by kamalesh17, 11 months ago

by using identity evaluate the 1+1/8-27/8?​

Answers

Answered by vikasrajput8597
9

Answer:

1+ (1/2)^3-(3/2)^3

=1+(1/2-3/2){(1/2)^2+1/2*3*2+(3/2)2}

=1+(-1){1/4+3/4+9/4}

=1+(-1)(13/4)

=1-13/4

=-9/4

Answered by streetburner
0

Explanation:

1+1/8-27/8 = 1 + 0.5^3 - 1.5^3

= 1 - (1.5^3 - 0.5^3)

= 1 - (1)(1.5² + 0.5² + 0.75)

= 1 - (2.25 + 0.25 + 0.75)

= 1-(3.25)

= - 2.25

Similar questions