Question

A can do a piece of work in 12 days, and B in 15 days. They work together for 5 days and then B left. The days taken A to finish the remaining work is :
A. 3 days
B. 5 days
C. 10 days
D. 121 days

Answer 1

Answer:

Step-by-step explanation:

work done by A=1/12

work done by B=1/15

together they worked in one day=(1/12)+(1/15)

=(4+5)/60

=3/20

5 days work =15/20

i.e.,3/4

remaining work=1/4

1 day---->1/12

?---->1/4 work

3 days

Answer 2

Answer:

let a and b do 1 work

work done by a + b in 1 day = 1/12+1/15=3/20

work done by a + b in 5 days = 3/20*5=3/4

B lefts the work.

work left to do = 1-3/4

=1/4

work done by a in 1 day=1/12

work done by a in 1/4 days=1/12/1/4

=1/12*4=3

A takes 3 days to complete the work.

Hope it helps u.