Question

a can do a piece of work in 12 days b in 16 days they worked together on it for 3days and a left .how long did b take to finish the remaining work​

Answer 1

Answer:

9 Days

Step-by-step explanation:

A's one day's work=1/12

B's one day's work=1/16

(A+B)'s 3 Days work=3(1/12+1/16)

=3(4+3/48)

=3×7/48

=7/16

Remaining work=1-7/16

=9/16

Remaining work done by B

so time taken by B=9/16×16

=9 Days

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Answer 2

Time taken by A in 1 hour=1/12

Tima taken ,, B ,, 1 , , =1/16

They worked together = 1/12 plus 1/16

=7/48

For 3 days = 7/48multiply 3

=7/16

Total amount = (1- 7/16)

9/16

Step-by-step explanation:

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