A can do a piece of work in 12 days. if he is joined by b who is 50% more efficient, in how many days will a and b together finish the work ?
Answers
Answered by
0
b=a+50%ofa=150a/100=3/2a
a×12=(a+b)x
12A=(A+3/2A)x
12A=5A/2x
x=24/5=4.8 days..
please mark it as a brainliest answer
a×12=(a+b)x
12A=(A+3/2A)x
12A=5A/2x
x=24/5=4.8 days..
please mark it as a brainliest answer
Answered by
3
12 days
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EXPLANATION
..........
TOTAL WORK = 18 Chocolates
B is 50% efficient than A. So, B eats 1.5 chocolates per day.
So, time taken by B = [18 / 1.5 ]
= 12 days
*********************************************
HOPE THIS HELPS YOU
*********************************************
-------------------------------------
EXPLANATION
..........
TOTAL WORK = 18 Chocolates
B is 50% efficient than A. So, B eats 1.5 chocolates per day.
So, time taken by B = [18 / 1.5 ]
= 12 days
*********************************************
HOPE THIS HELPS YOU
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