A can do a piece of work in 12 hours ,B and C can do it in 3 hours whereas A and C can do it in 6 hours.how long will B alone take to do the same work
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correct answer is 4 hrs. I hope that it helps you.
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B alone will take to do the same work in 4 hours.
Let the total work done be LCM of (12,3,6) = 12 units.
Given A can do the work in 12 hours.
So, work per hour done by A = 12/12 = 1 unit.
Given, A and C together can do the work in 6 hours.
So, work per hour done by both A and C = 12/6 = 2 units.
So, C alone can complete (2-1) units = 1 unit of work per hour.
Given, B and C together can do the work in 3 hours.
So, work per hour done by both B and C = 12/3 = 4 units.
So, B alone can complete (4-1) units = 3 unit of work per hour.
3 units of work B does in 1 hour.
From unitary method, 1 unit of work is done by B in (1/3) hours.
Similarly, 12 units (required) work is done by B in (12/3) = 4 hours.
So, B takes 4 hours.
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