A can do a piece of work in 120 days and B can do it in 150 days.They worked together for 20 days.then B leaves and A alone continue the work.After C joins A and the work is completed in 48 days more.In how many days C can do the whole work alone?.
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Answer:A one days work = 1/120
B one days work = 1/150
(A+B) one days = 1/120+1/150=3/200
(A+B) 20 day work =3/200×20=3/10
A s 12 days work =1/120×12=1/10
C join =3/10+1/10=2/5
Ramining work =(1-2)/5=3/5
(A+C)48 days work =3/5×1/48=1/80
C one days work =1/80-1/20=1/240
C days=240 Ans
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