A can do a piece of work in 14 days which B alone can do in 21 days. They
begin together but 3 days before the completion of the work, A leaves off. The
total number of days for the work to be completed is
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Answer:
A=1/14
B=1/21
1/14+1/21=(3+2)/42
Total work 42 days
A's one day work 3
B's one day work 2
Last 3 days done by only B so 2*3=6 work
Remaining work 42-6=36 work completed by A and B
A+B one day work 5
Remaining 36 work done by A and B
36/5=7.2
Total time=7.2+3=10.2 days
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