Question

A can do a piece of work in 14 days while B can do it in 21 days .They began together and worked at it for 6 days .then,A fell ill and B had to complete the remaining work alone. In how many days was the work completed ​

Answer 1

Answer:

A's one day work=1/14

B's one day work=1/21

{A+B} one day work=1/14+1/21=5/42

they both work 6 day =5/42*6=5/7

B had to complete the remainig work=1-5/7=2/7

B had to complete the work=2/7 divided by 1/21

divide change into mutiply=2/7*21/1=6

total time taken =6+6=12

Answer 2

Step-by-step explanation:

Let the work done by A and B for one day = 1/14 and 1/21

1/14+1/21=3+2/42

=5/42

Part of the work done by both of them in 6 days

5/42×6=5/7

Part of the work undone = 1-5/7=2/7

B can do the work in 21 days

Now B will do the work = 2/7×14=4

Here is your disgusting answer!! 4 days.

Mark me as Brainliest!!