A can do a piece of work in 14 days while B can do it in 21 days. They began together and worked it for 6 days. Then, A fell ill and B had to complete the remaining work alone. In how many days was the work Completed
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Answered by
524
A's one day work=1/14
B's one day work=1/21
{A+B} one day work=1/14+1/21=5/42
they both work 6 day =5/42*6=5/7
B had to complete the remainig work=1-5/7=2/7
B had to complete the work=2/7 divided by 1/21
divide change into mutiply=2/7*21/1=6
total time taken =6+6=12
B's one day work=1/21
{A+B} one day work=1/14+1/21=5/42
they both work 6 day =5/42*6=5/7
B had to complete the remainig work=1-5/7=2/7
B had to complete the work=2/7 divided by 1/21
divide change into mutiply=2/7*21/1=6
total time taken =6+6=12
yahyaahmad:
thank you so much
Answered by
95
Total day required to complete this work is 12
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