Question

If I is a zero of polynomial p(x)=ax^2-(a-1)x-1, then
find the value of a​

Answer 1

Answer:

a=1

Step-by-step explanation:

p(x)=ax²-(a-1)x-1

Given that 1 is a zero of p ( x).

So,p(1)=0

=> a×1²-(1-1)x-1=0

=> a-1=0

a=1.

Thus, the value of a is 1.

hope it will help you.