Question

In Figure 5, ABCD is a rectangle.
If angle CEB:angle ECB = 3:2,
find the measure of
i. angle ECB ii. angle AEC.​

Answer 1

Answer:

Angle DEF =126

THEREFORE,,, FCB=360-126-90 (ANGLE IN REC.ARE OF 90')

=144'

Let angleCEB =3x and ECB BE 2x

and

Angle BCF =CEB +EBC

144=3x +2x

144 =5x

x= 144/5

x = 28.8

Therefore, CEB = 3×28.8

=86.4

EBC= 2×28.8

=57.6

And, Angle AEC+CEB =180(LINEAR PAIR)

AEC+ 86.4=180

AEC=180-86.4

=93.6

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Help

You

Answer 2

Answer:

Step-by-step explanation:

Angle DEF =126

THEREFORE,,, FCB=360-126-90 (ANGLE IN REC.ARE OF 90')

=144'

Let angleCEB =3x and ECB BE 2x

and

Angle BCF =CEB +EBC

144=3x +2x

144 =5x

x= 144/5

x = 28.8

Therefore, CEB = 3×28.8

=86.4

EBC= 2×28.8

=57.6

And, Angle AEC+CEB =180(LINEAR PAIR)

AEC+ 86.4=180

AEC=180-86.4

=93.6