a can do a piece of work in 14 days while B can do it in 21 days they begin together and work for seven days then A fell ill and b
had to complete the work in how many days the work will completed
Answers
Answered by
3
Answer:
b will take 3.5 days
total time = 7 + 3.5 = 10.5 Days
Step-by-step explanation:
Let Say W is the work to be done
A do in 14 Days
A do in 1 day = W/14
B do in 1 day = W/21
Work done by A&B together in 1 day = W/14 + W/21 = 5W/42
Work done by A& B together in 7 Days = 7 * (5W/42) = 5W/6
Remaining work = W - 5W/6 = W/6
W/21 is done by B in 1 Day
so W/6 will be done by B = (1/W/21) * (W/6)
=(21/W)(W/6)
= 3.5 Days
Total time taken = 7 days together + 3.5 Days by B = 10.5 Days
Answered by
3
total work = 42 units
work done by both a(3 units) and b(2 units) in one day= 5 units
work done by both in 7 days = 5×7days=35 units
remaining work done by b (7 units)= 7/2 = 3.5 days
total days = 7+3.5=10.5 days
work done by both a(3 units) and b(2 units) in one day= 5 units
work done by both in 7 days = 5×7days=35 units
remaining work done by b (7 units)= 7/2 = 3.5 days
total days = 7+3.5=10.5 days
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