Question

A can do a piece of work in 15 days and b alone can do it in 10 days b works at it for 5 days and then leave a alone can finish the remaining work in _____

Answer 1

If B works at it for 5 days and leaves then A alone can finish the remaining work in 7.5 days.

Step-by-step explanation:

A can complete a work in 15 days

So, In 1-day, A can do = [$\frac{1}{15}$]th of work

B alone can do the work in 10 days

So, In 1-day, B can do = [$\frac{1}{10}$]th of work

But, it is given that B works only for 5 days and then leaves A alone

∴ Amount of work done by B in 5 days = $\frac{5}{10} = \frac{1}{2}$

So, The remaining amount of work that A will do alone is = 1 – ½ = ½

Now,

If  $\frac{1}{15}$th of work is done by A in 1 day

Then, ½ of the work will be done by A in = $\frac{15}{2}$ = 7.5 days.

Thus, A alone can finish the remaining work in 7.5 days.

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