find initial velocity of a car which is stopped by applying brake in 10 seconds the retardation due to the break is 2.5 m/s²
Answers
Answered by
3
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Here's your answer :
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v = 0
t = 10s
a = - 2.5m/s
From a = v - u/t
- 2.5 = v - 0/10
- 2.5×10 = - v
- 25 = - v
25 = v
Therefore, final velocity = 25 m/s.
================
Hope it helps.
================
Here's your answer :
==================
v = 0
t = 10s
a = - 2.5m/s
From a = v - u/t
- 2.5 = v - 0/10
- 2.5×10 = - v
- 25 = - v
25 = v
Therefore, final velocity = 25 m/s.
================
Hope it helps.
================
Attachments:
kingofworld:
a=-2.5
Answered by
3
u=?
v=0(brakes are applied)
t=10
retardation =2.5
so acceleration =-2.5
a=v-u/t
-2.5=0-u/10
-2.5×10=-u
u=25m/s
v=0(brakes are applied)
t=10
retardation =2.5
so acceleration =-2.5
a=v-u/t
-2.5=0-u/10
-2.5×10=-u
u=25m/s
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