Math, asked by devantemartin48, 1 year ago

Craig measured a length as 0.034 millimeters What is the margin of error?

Answers

Answered by QGP
2
Hey There!!

Here we are dealing with the concepts of Error Analysis and Significant Figures.


We are given that the measured length is 0.034 mm.


Here, the last digit 4 is uncertain. The scale can measure only with a resolution of 0.001 mm.


In other words, we do not what exactly was the measurement. It could have been slightly lesser than 0.034 mm (like it could be 0.0339 mm). It could also have been slightly greater than 0.034 mm (like it could be 0.0342 mm)

However, Craig is limited by the resolution of his scale. He cannot measure distances smaller than 0.001 mm.


Thus, 0.001 mm is the Least Count of the scale.

This way, the error becomes \pm 0.001 \, \, mm

You can say that the actual value lies between 0.033 mm and 0.035 mm. This is a range of 0.002 mm.


Hope it helps
Purva
Brainly Community

Answered by Ᏸυէէєɾϝɭყ
2

Answer:

Hey There!!

Here we are dealing with the concepts of Error Analysis and Significant Figures.

We are given that the measured length is 0.034 mm.

Here, the last digit 4 is uncertain. The scale can measure only with a resolution of 0.001 mm.

In other words, we do not what exactly was the measurement. It could have been slightly lesser than 0.034 mm (like it could be 0.0339 mm). It could also have been slightly greater than 0.034 mm (like it could be 0.0342 mm)

However, Craig is limited by the resolution of his scale. He cannot measure distances smaller than 0.001 mm.

Thus, 0.001 mm is the Least Count of the scale.

This way, the error becomes \pm 0.001 \, \, mm

You can say that the actual value lies between 0.033 mm and 0.035 mm. This is a range of 0.002 mm.

Hope it helps

Purva

Brainly Community

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