Math, asked by PRINCE9050, 1 year ago

A can do a piece of work in 15 days and B is 50% more effecexpensive by A. what is time take by B is complete that works.

Answers

Answered by jackcrispus
1
15 = 150% of B
B = 15 * 100/150
B = 10 days
Answered by amitelectronicp4jnqp
0
work done by A in one day =1/15
work done by B in one day=(100+50/100)*1/15=1/10
so time required by B=10 days
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