English, asked by aryab28t, 17 days ago

A can do a piece of work in 20 days . B is 60% more efficient than A. B can finish it in ________ days. *​

Answers

Answered by sunisri1999
1

Hint: Find the fraction of the total work A does in one day. Hence find the fraction of the total work B does in one day. Hence find the total number of days it takes B to finish the job. Verify your answer.

Complete step-by-step answer:

A completes one job in 12 days.

Hence the fraction of job completed by A in 1 day =112.

Since B is 60% more efficient than A, the fraction of the total job completed on one day by B will be 60% more than that of A.

Hence the fraction of the total job completed by B on one day =112+60100×112=5+360=860=215

Hence the total number of days in which B can finish the job is 1215=152=7.5

Hence B finishes the job in 7.5 days.

Hence option b is correct.

Note: Verification:

One day work of A = 112th of total work

One day work of B =17.5th=215th of total work.

Efficiency of B over A =215−112112×100=8−55×100=60

Hence B is 60% more efficient than A.

Hence our answer is verified to be correct.

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