Question

A can do a piece of work in 20 days which B alone can do in 12 Days B worked at it for nine days then A can finish the remaining work in

Answer 1

Answer:

Let us suppose the no. of days A will take to finish the work be X.

Then work done by A in one day will be 1/X

But A takes 3 times longer than B                         (given)

That means, work done by B in one day will be

1/X multiplied by 3 which is 3/X

now, the total work done by both A and B in one day will be-

1/X+3/X = 4/X

they take 9 days to complete the work, which means the total quantity of the work is -

4/X multiplied by 9 = 36/X

now, we know that A can do 1/X work in one day and the total work is 36/X, so for calculating the no. of days taken by him, we divide the total work by his one day's work --

36/X divided by 1/X

which will be

36/X * X/1

= 36

so, A will take 36 days to finish the work

Step-by-step explanation: