A can do a piece of work in 24 days and B can do same work in 30 days. working for 8 days together A leaves and remaining working is done by B alone. In how many days does B complete remaing work.
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Answer:
12 days
Step-by-step explanation:
A's 1 day work= 1/24
B's 1 day work= 1/30
(A+B)'s 1 day work= 1/24 + 1/30
= 3/40
They work together for 8 days.
= (3/40) × 8
= 3/5 part of work completed. So, remaining work is 2/5. This remaining work completed alone by B
= (2/5)×30
= 12 days
B can complete the remaining work in 12 days
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