Math, asked by rameswar5672, 2 months ago

A table cover of dimensions 3m 25 cm and 2m 30 cm is spread on a table.If 30 cm of the cover is hanging all around the table.Find the area of the hanging covers.Also find the cost of polishing the table top at ₹16 per m.sq.​

Answers

Answered by MrAnonymous412
104

  \underline{\large \bf\: Given :-}

 \\  \star \:  \rm \: length \: of \: cover \:  = 3 \: m \: 2 5 \: cm \:  = 3.25m \:  \\ \\   \:  \:  \star \: \rm \: breadth \: of \: cover \:  = 2 \: m \: 30\: cm \:  = 2.30m\: \\ \\

  \underline{\large \bf\: Solution:-}

To find the cost of polishing the table top ,we have to find out it's area ,

Now ,

 \\  \sf \: Area\: of\: table\: cover= 3.25 × 2.30 = \red{ 7.475 m²} \\

Give, 30 cm width of cloth is outside the table an each side ,

Hence,

 \\  \star\:  \:  \:   \sf \: Length\: of\: table = 3.25 - 2 × 0.30  \\

 \\  \:  \: \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \sf \:  \:  \:  \:  \:  \:  \:  \:  \:  :  \:  \implies \: 3.25 \:  -  \: 0.6

 \\    \:  \:  \:  \:  \:  \:  \:  \:  \:  \sf \:  \:  \:  \:  \:  \:  \:  \:  \:  :  \:  \implies   \boxed{\underline\green{\frak{ 2.65 \: m}}} \\

 \\  \star\:  \:  \:   \sf \: breadth\: of\: table = 3.25 - 2 × 0.30  \\

 \\  \:  \: \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \sf \:  \:  \:  \:  \:  \:  \:  \:  \:  :  \:  \implies \: 2.30 \:  -  \: 0.6

 \\    \:  \:  \:  \:  \:  \:  \:  \:  \:  \sf \:  \:  \:  \:  \:  \:  \:  \:  \:  :  \:  \implies   \boxed{\underline\green{\frak{ 1.70m}}} \\

Now , Area of top table ,

 \\  \:  \: \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \sf \:  \:  \:  \:  \:  \:  \:  \:  \:  :  \:  \implies \: 2.65 \:    \times  \: 1.70

 \\    \:  \:  \:  \:  \:  \:  \:  \:  \:  \sf \:  \:  \:  \:  \:  \:  \:  \:  \:  :  \:  \implies   \boxed{\underline\pink{\frak{ 4.505 \: m ^{2} }}} \\

So,

 \\  \blue{  \boxed{\sf \underline{ Area  \: of \:  hanging  \: cover \:  of \:  table \:  =  \: Area  \: of \:  cover  \: of \:  table \:  -  \: Area \:  of \:  the  \: top \:  of \:  table \:  }}} \\

 \\  \:  \: \: \:  \: \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \sf \:  \:  \:  \:  \:  \:  \:  \:  \:  :  \:  \implies \:7.45 \:     - 4.505 \: \\

 \\  \:  \: \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \:  \:  \:  \:  \:  \:  \:  \:  \:  \sf \:  \:  \:  \:  \:  \:  \:  \:  \:  :  \:  \implies   \boxed{\underline\pink{\frak{ 2.97 \: m ^{2} }}} \\

It has been given that Rs. 16 per m² is the cost of polishing the table.

So,

 \\  \:  \:  \:  \:  \:  \underline{ \sf \: cost \: of \: polishing \: top \: of \: table \:  =  \: 16 \times area \: of \: top \: of \: table} \\

 \\  \:   \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \sf \:  \:  \:  \:  \:  \:  \:  \:  \:  :  \:  \implies \:16 \times 4.505

 \\  \:  \: \:  \:  \:  \:  \:  \: \:  \:  \:  \:  \:  \:  \:  \:  \:  \sf \:  \:  \:  \:  \:  \:  \:  \:  \:  :  \:  \implies   \boxed{\underline\pink{\frak{Rs \: 72.08 }}} \\

 \:  \:  \red {\rm \underline{ So,  \: Rs. \:  72.08 \:  will  \: be  \: needed  \: to \:  polish  \: the  \: top   \: }}

 \:

Be brainly ♡


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