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Answer these maths Question:-

a)If a side is 40cm of a square then calculate it's area and perimeter.

b) What is the width of a rectangle, if it's area is 220cm² and length is 22cm.

c)What is the thickness of one

notebook if a bundle of f one note. 12 notebook height is 75 cm ?

d)What will be the breath of carpet if the Length is 36 m and area is 422 m² of hall?

e)Calculate the number of tiles required for tiling the floor, if the size of tile is 3×2cm and area of floor is 660 cm²?

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## Answers

**Question **

a) A side is 40 cm of a square then calculate it's area and perimeter.

__•____ ____G____i____v____e____n____ __

- Side of square = 40 cm

__•____ ____T____o____ ____f____i____n____d____ __

- Area and perimeter of square

__•____ ____S____o____l____u____t____i____o____n____ __

Area of square = side × side

⟶ 40 × 40

⟶ 1600 cm²

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Perimeter of square = 4 × side

⟶ 4 × 40

⟶ 160 cm

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b) What is the width of a rectangle, if it's area is 220cm² and length is 22cm.

__•____ ____Giv____e____n____ __

- Area of rectangle = 220 cm²
- Length of the rectangle = 22 cm

__•____ ____T____o____ ____f____i____n____d____ __

- Width of the rectangle

__•____ ____S____o____l____u____t____i____o____n____ __

Area of rectangle = length × breadth

⟶ 220 = 22 × breadth

⟶ 220/22 = breadth

⟶ 10 = breadth

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c)What is the thickness of one notebook __i____f____ ____t____h____i____c____k____n____e____s____s____ ____o____f____ ____1____2____ ____n____o____t____e____b____o____o____k____s____ ____i____s____ ____7____5____ ____c____m____.__

__•____ ____G____i____v____e____n____ __

- Thickness of 12 notebooks = 75 cm

__•____ ____T____o____ ____f____i____n____d____ __

- Thickness of one notebook

__•____ ____S____o____l____u____t____i____o____n____ __

Thickness of 12 notebooks = 75 cm

Thickness of 1 notebook = 75/12 cm = 6.25 cm

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**Questio****n**** **

d)What will be the breath of carpet if the Length is 36 m and area is 422 m² of hall?

__•____ ____G____i____v____e____n____ __

- Length = 36 m
- Area = 422 m²

__•____ ____T____o____ ____f____i____n____d____ __

- Breadth of the carpet

__•____ ____S____o____l____u____t____i____o____n____ __

Area = length × breadth

⟶ 422 = 36 × breadth

⟶ 422/36 = breadth

⟶ 11.72 m

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** **

e)Calculate the number of tiles required for tiling the floor, if the size of tile is 3×2cm and area of floor is 660 cm²?

__•____ ____G____i____v____e____n____ __

- Size of the tiles = 3 × 2 cm
- Area of the floor = 660 cm²

__•____ ____T____o____ ____f____i____n____d____ __

- No. of tiles required for tiling the floor

__•____ ____S____o____l____u____t____i____o____n____ __

Area of the tiles = length × breadth

⟶ 3 × 2

⟶ 6 cm²

No. of tiles required = Area of floor/ Area of floor

⟶ 660/6

⟶ 110 tiles

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