Answer these maths Question:-
a)If a side is 40cm of a square then calculate it's area and perimeter.
b) What is the width of a rectangle, if it's area is 220cm² and length is 22cm.
c)What is the thickness of one
notebook if a bundle of f one note. 12 notebook height is 75 cm ?
d)What will be the breath of carpet if the Length is 36 m and area is 422 m² of hall?
e)Calculate the number of tiles required for tiling the floor, if the size of tile is 3×2cm and area of floor is 660 cm²?
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Answers
Question
a) A side is 40 cm of a square then calculate it's area and perimeter.
• Given
- Side of square = 40 cm
• To find
- Area and perimeter of square
• Solution
Area of square = side × side
⟶ 40 × 40
⟶ 1600 cm²
- Area of square = 1600 cm²
Perimeter of square = 4 × side
⟶ 4 × 40
⟶ 160 cm
- Perimeter of square = 160 cm
Question
b) What is the width of a rectangle, if it's area is 220cm² and length is 22cm.
• Given
- Area of rectangle = 220 cm²
- Length of the rectangle = 22 cm
• To find
- Width of the rectangle
• Solution
Area of rectangle = length × breadth
⟶ 220 = 22 × breadth
⟶ 220/22 = breadth
⟶ 10 = breadth
- Breadth of the rectangle = 10 cm
Correct Question
c)What is the thickness of one notebook if thickness of 12 notebooks is 75 cm.
• Given
- Thickness of 12 notebooks = 75 cm
• To find
- Thickness of one notebook
• Solution
Thickness of 12 notebooks = 75 cm
Thickness of 1 notebook = 75/12 cm = 6.25 cm
- Height of 1 notebook = 6.25 cm
Question
d)What will be the breath of carpet if the Length is 36 m and area is 422 m² of hall?
• Given
- Length = 36 m
- Area = 422 m²
• To find
- Breadth of the carpet
• Solution
Area = length × breadth
⟶ 422 = 36 × breadth
⟶ 422/36 = breadth
⟶ 11.72 m
- Breadth = 11.72 m
Question
e)Calculate the number of tiles required for tiling the floor, if the size of tile is 3×2cm and area of floor is 660 cm²?
• Given
- Size of the tiles = 3 × 2 cm
- Area of the floor = 660 cm²
• To find
- No. of tiles required for tiling the floor
• Solution
Area of the tiles = length × breadth
⟶ 3 × 2
⟶ 6 cm²
No. of tiles required = Area of floor/ Area of floor
⟶ 660/6
⟶ 110 tiles
- No. of tiles required = 110 tiles