Math, asked by luckyverma873, 4 months ago

A can do a piece of work in 24 days, B in 52 days and C in 64 days. All begin to do it together but A leaves after 6 days and C leaves 6 days before the completion

of the work. How many days did the work last?​

Answers

Answered by prasanthikuchipudi
1

Answer:

24 6/29

Step-by-step explanation:

A can do a piece of work in 1/24 days

B can do a piece of work in 1/52 days

C can do a piece of work in 1/64 days

A leaves after 6 days

A did 6/24 days

Let 'x; be the complete working days

C leave 6 days before completion of work (x-6)/64

B did worked for last x/52

A+B+C=1(complete work)

6/24+x/52+(x-6)/64=1

LCM of 24,52,64 is 2496

6*104+x*48+39(x-6)=2496

624+48x+39x-234=2496

87x=2106

x=24 6/29

Brainlist to my answer

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