Question

A can do a piece of work in 24 days. If B is 60% more efficient than A, then the number of days required by B to do the same piece of work is:

Answer 1

Answer: 15 days

Step-by-step explanation:

A does work in 24 days

so A's one day work = 1/24

B is 60% more efficient than A

B's one day work= 1/24 + (60/100 × 1/24)

                           ⇒1/24 ( 1 + 60/100)

                           ⇒160/2400

                           ⇒1/15

thus B takes 15 days to complete the same work.

Answer 2

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Question

A can do a piece of work in 24 days. B is 60% more efficient than A. The number of days B take to do the same piece of work is

Answer:

$\Large\fbox\red{15\: Days\:\:(or)\:\:14.4\:Days}$

Solution

Let the work done by A be x so,

x = 24 days

As per the question , 60% of x = b

$x \times \frac{60}{100}$

$= \frac{3}{5} \times x$ = B's work

Now

If x = 24 days then,

$x\times \frac{3}{5} = \frac{24}{ x} \times x \times \frac{3}{5}$

$= \frac{72}{5} = 14.4$

Therefore, B can do the work in 14.4 days (or) 15days.

Hope it helps uh!!

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