Question

A can do a piece of work in 24 days. If B is 60%
more efficient than A, then the number of days
required by B to do the twice as large as the
earlier work is -

(a) 24
(c) 15
(b) 36
(d) 30
step by step explanation??​

Answer 1

we need to find the number of days B will take to finish work that is twice as big as the work A did.

we don't know how much work A did in a day so lets wrote it as :

1÷24

so to find the rest we do :

1÷24 + 60÷100 x 1÷24

= 10/240 + 6/240 = 16/240

= 1/15

so now we have to find the number of days he will take to do twice the work so :

= 15 x 2 = 30 days

so the correct option is 'd'.

THIS TOOK ME WHILE SO I WOULD APPRECIATE IF YOU COULD GIVE ME BRAINLIEST :))